*Post by bassam king karzeddin**Post by bassam king karzeddin*Where, (p > 2, q) are prime numbers

Of course, this was proven to you over and over in my posts at the sci.math, the Math forum, and Quora, plus Stalk Exchange (where they had hidden my proofs earlier)

So, I thought those people might understand by the time, but it seems so hopeless case with the vast majorities of them, so I repeated the Question for them thinking that the smart professionals would finally get my hints, but immediately was downvoted and closed, refusing to even have a little chance to understand their dogmatic old beliefs about real numbers were completely non-sense and so meaningless

https://mathoverflow.net/questions/288089/why-does-fermats-last-theorem-invalidate-the-existence-of-many-real-algebraic-n?noredirect=1#comment713057_288089

So, can a smart clever professional who correctly understands my simplest proofs save those dogmatic people from their own minds, please?

or must I teach every professional mathematician alone about those very simple facts that do require only a drop of humanity first and a drop of intelligence second? wonder!

Presently, I'm not allowed to post at MSE nor at HSE

And since this was the last place for me to post at Overflow Mathematics at SE SO, Please rescue those astray people before they go mad, for sure

Regards

Bassam King Karzeddin

Dec. 9th, 2017

A very rigorous proof (that nobody on earth can deny) would be a solution to a cubic polynomial of this form and for sure

(x^9 - x^3 - 1 = 0)

Please, feel free to represent your real root to any degree of accuracy you would like to, and see how easy it contradicts the PROVEN Fermat's last theorem

And if you are convensend now (after hundreds of FREE lectures) that no real root actually exists, then confess it so openly and loudly (if you have a very little drop of humanity first, and second,a very little drop of intelligence too)

But if you still want to talk nonsense as usual, then better keep it for yourself, since it is not at all helpful, for sure

Regards

Bassam Karzeddin

Dec. 23ed, 2017

*Post by bassam king karzeddin*Where, (p > 2, q) are prime numbers

Of course, this was proven to you over and over in my posts at the sci.math, the Math forum, and Quora, plus Stalk Exchange (where they had hidden my proofs earlier)

So, I thought those people might understand by the time, but it seems so hopeless case with the vast majorities of them, so I repeated the Question for them thinking that the smart professionals would finally get my hints, but immediately was downvoted and closed, refusing to even have a little chance to understand their dogmatic old beliefs about real numbers were completely non-sense and so meaningless

https://mathoverflow.net/questions/288089/why-does-fermats-last-theorem-invalidate-the-existence-of-many-real-algebraic-n?noredirect=1#comment713057_288089

So, can a smart clever professional who correctly understands my simplest proofs save those dogmatic people from their own minds, please?

or must I teach every professional mathematician alone about those very simple facts that do require only a drop of humanity first and a drop of intelligence second? wonder!

Presently, I'm not allowed to post at MSE nor at HSE

And since this was the last place for me to post at Overflow Mathematics at SE SO, Please rescue those astray people before they go mad, for sure

Regards

Bassam King Karzeddin

Dec. 9th, 2017

A very rigorous proof (that nobody on earth can deny) would be a solution to a cubic polynomial of this form and for sure

(x^9 - x^3 - 1 = 0)

Please, feel free to represent your real root to any degree of accuracy you would like to, and see how easy it contradicts the PROVEN Fermat's last theorem

And if you are convensend now (after hundreds of FREE lectures) that no real root actually exists, then confess it so openly and loudly (if you have a very little drop of humanity first, and second,a very little drop of intelligence too)

But if you still want to talk nonsense as usual, then better keep it for yourself, since it is not at all helpful, for sure

Regards

Bassam Karzeddin

Dec. 23ed, 2017

I have just ask it at Quora, of course after posting it here since they are (MODERATED site) that is not trusted at all, for sure

but strangely, 1500 views with one useless answer and 6 members wanting an answer within only (15) minutes, wonder!

Link here: https://www.quora.com/Can-you-solve-this-odd-degree-polynomial-for-only-one-real-root-x-9-x-3-1-no-matter-the-degree-of-accuracy-you-would-like-to-obtain

Let me try later to re edit my same Question (providing this example) with that SE moron site, to see whether they can tolerate any more of my mathematical bombs over their so tinny heads, wonder!