Discussion:
Was the Cardano formula for cubic equations refuted recently?
bassam king karzeddin
2017-05-11 17:58:19 UTC
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!

Regards
Bassam King Karzeddin
11 May 2017
bassam king karzeddin
2017-05-13 08:51:06 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
I thought really this was a very easy question now to many clever school students, especially that I had posted the answer even before asking the question, wonder! and for sure also

BKK
bassam king karzeddin
2017-05-13 12:17:51 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!

And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure

So, here it is again and again until you get it

Consider this simple Diophantine equation

n^3 = m^3 + nm^2
Where (n, m) are coprime integers

So what are the integer solutions?

Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case

Otherwise, factor the equation, you get:

(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)

So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)

But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure

So here you observe carefully their endless confusions as their endless numbers

A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics

So, the insolvable Diophantine equation provided above (n^3 = m^3 + nm^2) would become so simply as the following:

(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)

And further, the peculiar genius from the history of mathematics, reduce the problem by simplifying it more, where he let the unknown (n/m) as equals to (x), and then substitute, you get the following WONDERFUL irreducible cubic polynomial:

(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed

And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)

But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure

So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations

And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure

Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore

Had you ever seen a Big Scandal than This one, wonder

Unfortunately, There are much more Bigger scandals than that for sure

Spread this proven fact please, for the sake of your collages and future generation too for sure

And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure

There is more to this issue ...!

Regards
Bassam King Karzeddin
May 13, 2017
bassam king karzeddin
2017-07-30 10:22:38 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!
And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure
So, here it is again and again until you get it
Consider this simple Diophantine equation
n^3 = m^3 + nm^2
Where (n, m) are coprime integers
So what are the integer solutions?
Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case
(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)
So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)
But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure
So here you observe carefully their endless confusions as their endless numbers
A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics
(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)
(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed
And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)
But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure
So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations
And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure
Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore
Had you ever seen a Big Scandal than This one, wonder
Unfortunately, There are much more Bigger scandals than that for sure
Spread this proven fact please, for the sake of your collages and future generation too for sure
And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure
There is more to this issue ...!
Regards
Bassam King Karzeddin
May 13, 2017
SO, Did you see clearly how the magicians create you a solution from nothing and for nothing but for more than mere fun indeed? wonder about those ...!

BKK
bassam king karzeddin
2017-09-30 09:44:15 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!
And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure
So, here it is again and again until you get it
Consider this simple Diophantine equation
n^3 = m^3 + nm^2
Where (n, m) are coprime integers
So what are the integer solutions?
Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case
(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)
So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)
But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure
So here you observe carefully their endless confusions as their endless numbers
A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics
(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)
(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed
And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)
But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure
So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations
And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure
Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore
Had you ever seen a Big Scandal than This one, wonder
Unfortunately, There are much more Bigger scandals than that for sure
Spread this proven fact please, for the sake of your collages and future generation too for sure
And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure
There is more to this issue ...!
Regards
Bassam King Karzeddin
May 13, 2017
@Zelos

Did you understand this well-illustrated example first? wonder!

It is more than easy for any clever student I swear for sure

Check-up first in the so shameful history of mathematics, wither the cubic root operation had really a proof or only smart conclusion for sure

Noting that only square root operation was proved rigorously from the Pythagorean Theorem, that gave birth to existing constructible numbers ONLY

But, yes when only the constructible number is a cube, then naturally it has a cubic root EXISTS

In short, the general cubic root operation or higher p'th root operation are refuted so easily

In fact, the truthiness of those fake operation would imply the un-truthness of Fermat's last theorem, but the later was proved true, wasn't it? wonder!

I had explained that quite many times in my posts

The main issue is that sweet approximation that deceives the human mind so easily, and we know that even a carpenter can make a cube box size for any non-cubic-number quite nicely (APPROXIMATELY), exactly like mathematics does with more accuracy (That is all)

BKK
Zelos Malum
2017-09-30 13:16:07 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!
And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure
So, here it is again and again until you get it
Consider this simple Diophantine equation
n^3 = m^3 + nm^2
Where (n, m) are coprime integers
So what are the integer solutions?
Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case
(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)
So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)
But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure
So here you observe carefully their endless confusions as their endless numbers
A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics
(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)
(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed
And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)
But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure
So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations
And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure
Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore
Had you ever seen a Big Scandal than This one, wonder
Unfortunately, There are much more Bigger scandals than that for sure
Spread this proven fact please, for the sake of your collages and future generation too for sure
And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure
There is more to this issue ...!
Regards
Bassam King Karzeddin
May 13, 2017
@Zelos
Did you understand this well-illustrated example first? wonder!
It is more than easy for any clever student I swear for sure
Check-up first in the so shameful history of mathematics, wither the cubic root operation had really a proof or only smart conclusion for sure
Noting that only square root operation was proved rigorously from the Pythagorean Theorem, that gave birth to existing constructible numbers ONLY
But, yes when only the constructible number is a cube, then naturally it has a cubic root EXISTS
In short, the general cubic root operation or higher p'th root operation are refuted so easily
In fact, the truthiness of those fake operation would imply the un-truthness of Fermat's last theorem, but the later was proved true, wasn't it? wonder!
I had explained that quite many times in my posts
The main issue is that sweet approximation that deceives the human mind so easily, and we know that even a carpenter can make a cube box size for any non-cubic-number quite nicely (APPROXIMATELY), exactly like mathematics does with more accuracy (That is all)
BKK
Again, stop wondering and start learning.

I know the history of mathematics, nothign shameful there. Your idiocy does not make it shameful

bassam king karzeddin
2017-09-30 14:32:39 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!
And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure
So, here it is again and again until you get it
Consider this simple Diophantine equation
n^3 = m^3 + nm^2
Where (n, m) are coprime integers
So what are the integer solutions?
Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case
(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)
So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)
But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure
So here you observe carefully their endless confusions as their endless numbers
A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics
(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)
(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed
And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)
But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure
So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations
And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure
Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore
Had you ever seen a Big Scandal than This one, wonder
Unfortunately, There are much more Bigger scandals than that for sure
Spread this proven fact please, for the sake of your collages and future generation too for sure
And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure
There is more to this issue ...!
Regards
Bassam King Karzeddin
May 13, 2017
@Zelos
Did you understand this well-illustrated example first? wonder!
It is more than easy for any clever student I swear for sure
Check-up first in the so shameful history of mathematics, wither the cubic root operation had really a proof or only smart conclusion for sure
Noting that only square root operation was proved rigorously from the Pythagorean Theorem, that gave birth to existing constructible numbers ONLY
But, yes when only the constructible number is a cube, then naturally it has a cubic root EXISTS
In short, the general cubic root operation or higher p'th root operation are refuted so easily
In fact, the truthiness of those fake operation would imply the un-truthness of Fermat's last theorem, but the later was proved true, wasn't it? wonder!
I had explained that quite many times in my posts
The main issue is that sweet approximation that deceives the human mind so easily, and we know that even a carpenter can make a cube box size for any non-cubic-number quite nicely (APPROXIMATELY), exactly like mathematics does with more accuracy (That is all)
BKK
30/09/2017, 5:32 pm
bassam king karzeddin
2018-02-13 08:50:22 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Maybe the students need more help in this regard since the professionals are so embarrassed to explain it to them and step by step, since it is published here and not the usual way from top Journals or top universities with so long proof and many tons of references, wonder!
And you become an expert in it, and so simply expand the simplest concept to any general polynomial for sure, where then you can help your teacher to get it only from the first look, and it is indeed more than easy for sure
So, here it is again and again until you get it
Consider this simple Diophantine equation
n^3 = m^3 + nm^2
Where (n, m) are coprime integers
So what are the integer solutions?
Any average student would immediately notice that (n = 0), and (m = 0) is the only solution, so we can drop this solution for being helpless case
(n - m)(n^2 + nm + m^2) = nm^2
And since we have gcd(n, m) = 1, then let (n - m = k), where k is integer prime to both (n & m)
So (k) divides exactly the LHS of the equation, but (k) does not divide the RHS of the same equation, which implies not even a single solution exists in the whole set of nonzero integers for sure (really too... easy for students)
But let us see how the top scientist professional mathematicians create deliberately a real solution for this problem, and naturally with very long talks and so many definitions or decisions they fakely adopt and so smartly convince the innocent students of their fake proof, for sure
So here you observe carefully their endless confusions as their endless numbers
A genius professional mathematicians (from the history) would immediately suggest to divide the whole equation by (m^3), where (m =/= 0), since division by zero isn't defined in mathematics
(n/m)^3 - (n/m) - 1 = 0, (try it yourself, since it is too ... easy)
(X^3 - X - 1 = 0), Where this must have three roots or solutions (in our damn modern mathematics), and according to Cardano famous formula discovered in 1545, such that one of them at least must be real solution since this invented polynomial (out of nothing), of odd degree, (of course they call it irrational real solution (in their mind), with endless digits, but always they present it in rational form, since there is no other meaningful way), all that to satisfy the baseless Fundamental Theorem Of al Gebra, so wonderful trick indeed
And their solution in any number system (say in 10base number system for simplicity, would be expressed as [N(m) / 10^{m - 1}], where (m) is positive integer, N(m) is positive integer with (m) sequence of digits, which is a rational approximation for an irrational number (in their minds only)
But evert student knows that solution would require (m), and hence N(m) to be positive integer with infinite sequence of digits, which is not defined nor accepted in principle of mathematics, ethics, besides being impossible task for sure
So, you had just seen the fabricated fake solution from nonsolvable Diophantine equations
And believe it that no Journals on earth would accept to publish this scandal for only too silly reasons of madness and meaningless egoistic personal problems mainly with alleged top professional mathematicians for sure
Not only that but the cubic FORMULA of (Able - Ruffini, and Galois theorems) gives that same real solution too, which makes it fake and not general anymore
Had you ever seen a Big Scandal than This one, wonder
Unfortunately, There are much more Bigger scandals than that for sure
Spread this proven fact please, for the sake of your collages and future generation too for sure
And one important matter you should realize fast, that is whenever you notice a numerical solution of any mathematical problem is dragging you endlessly, either in a sum or product operations, then make sure that you are on the way to that Fools Paradise (Infinity), that is never there, for sure
And by the way, nobody from the professionals dared to refute it, nor they would accept it for very known explained reasons for sure
There is more to this issue ...!
Regards
Bassam King Karzeddin
May 13, 2017
******
Peter Percival
2017-05-13 20:11:18 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No. It's correctness can be seen by substituting the solutions that it
produces back into the cubic. This is a tedious (but fool-proof) method
best done by a CAS.
Post by bassam king karzeddin
wonder!
Regards
Bassam King Karzeddin
11 May 2017
--
Do, as a concession to my poor wits, Lord Darlington, just explain
to me what you really mean.
I think I had better not, Duchess. Nowadays to be intelligible is
to be found out. -- Oscar Wilde, Lady Windermere's Fan
bassam king karzeddin
2017-05-14 06:43:18 UTC
Post by Peter Percival
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No. It's correctness can be seen by substituting the solutions that it
produces back into the cubic. This is a tedious (but fool-proof) method
best done by a CAS.
It is true that the Cardano formula works perfectly under very rare cases and only when the roots are real constructible numbers as mentioned and explained by me quite many times in other threads,

So, did you get the point? wonder!

BKK
Post by Peter Percival
Post by bassam king karzeddin
wonder!
Regards
Bassam King Karzeddin
11 May 2017
--
Do, as a concession to my poor wits, Lord Darlington, just explain
to me what you really mean.
I think I had better not, Duchess. Nowadays to be intelligible is
to be found out. -- Oscar Wilde, Lady Windermere's Fan
Zelos Malum
2017-09-28 10:14:57 UTC
Post by bassam king karzeddin
Post by Peter Percival
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No. It's correctness can be seen by substituting the solutions that it
produces back into the cubic. This is a tedious (but fool-proof) method
best done by a CAS.
It is true that the Cardano formula works perfectly under very rare cases and only when the roots are real constructible numbers as mentioned and explained by me quite many times in other threads,
So, did you get the point? wonder!
BKK
Post by Peter Percival
Post by bassam king karzeddin
wonder!
Regards
Bassam King Karzeddin
11 May 2017
--
Do, as a concession to my poor wits, Lord Darlington, just explain
to me what you really mean.
I think I had better not, Duchess. Nowadays to be intelligible is
to be found out. -- Oscar Wilde, Lady Windermere's Fan
No, it works in all cases because it makes no assumptions on it. It just works with the complex numbers which is algebraicly closed.
bassam king karzeddin
2017-09-20 18:04:15 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
It has no valid proof but only a very stupid conclusion and was refuted so easily
BKK
konyberg
2017-09-30 10:49:24 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
How is it refuted
ax^3 + bx^2 + cx + d = 0

Solution:

KON
konyberg
2017-09-30 10:59:36 UTC
Post by konyberg
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
How is it refuted
ax^3 + bx^2 + cx + d = 0
b
KON
It is not refuted. It can, and always be done.
The first, second, cubic and the quantic equations is solvable. You know this!
Still you hesitate to acknowledge it.
Why?
KON
bassam king karzeddin
2017-09-30 12:58:02 UTC
Post by konyberg
Post by konyberg
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
How is it refuted
ax^3 + bx^2 + cx + d = 0
b
KON
It is not refuted. It can, and always be done.
The first, second, cubic and the quantic equations is solvable. You know this!
Still you hesitate to acknowledge it.
Why?
KON
FYI

Even the general quadratic Eqn. wasn't solved completely

And it is partly true, whenever the roots are only REAL constructible number

BKK
bassam king karzeddin
2018-01-09 18:19:55 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Yes, as no valid proof existed for cubic root operation in the history of mathematics, but on the contrary there is a proof of refutation of such an operation, For sure
BKK
Zelos Malum
2018-02-15 14:14:11 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Yes, as no valid proof existed for cubic root operation in the history of mathematics, but on the contrary there is a proof of refutation of such an operation, For sure
BKK
considering we can construct it, you are simply wrong.
bassam king karzeddin
2018-02-17 07:48:42 UTC
Post by Zelos Malum
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Yes, as no valid proof existed for cubic root operation in the history of mathematics, but on the contrary there is a proof of refutation of such an operation, For sure
BKK
considering we can construct it, you are simply wrong.
But you can't construct it generally, which is the whole problem for sure

BKK
Jan
2018-01-10 00:49:11 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No.

--
Jan
bassam king karzeddin
2018-01-10 09:12:32 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No.
--
Jan
Pythagoras theorem proves the square root operation rigorously for sure

But what theorem does prove the cube root operation OR higher prime root operation in mathematics? wonder!

And please don't tell me it was only concluded, since conclusions are never regarded as rigorous proofs, for sure
BKK
bassam king karzeddin
2018-01-10 13:36:54 UTC
Post by bassam king karzeddin
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently?
No.
--
Jan
Pythagoras theorem proves the square root operation rigorously for sure
But what theorem does prove the cube root operation OR higher prime root operation in mathematics? wonder!
And please don't tell me it was only concluded, since conclusions are never regarded as rigorous proofs, for sure
BKK
It seems that no true history for such mathematics as cube root of non-cube integers, but the question: How did that sneak into mathematics as facts? wonder!
Most likely for a little need of daily practical problems as how can we make a cube box that contains two unit cube, which practically and approximately can be done up to very convenient way, but never exactly, and it was exactly the case of (pi), where we did need it to know the area of a circle APPROXIMATELY, So no wonder how did those described as constants as (pi or 2^{1/3}) were well established as real numbers, despite the facts that they are absolutely non-existing numbers

But it should be noted that indeed there is a cube root of real numbers that are cubes numbers itself, for sure
BKK
bassam king karzeddin
2018-01-21 08:55:22 UTC
Post by bassam king karzeddin
Was the Cardano famous formula discovered in (1545) in mathematics for solutions of cubic polynomials roots refuted so easily recently? wonder!
Regards
Bassam King Karzeddin
11 May 2017
Not only that but many other well known formulas were refuted so badly as well, for sure

BKK
bassam king karzeddin
2018-03-01 18:37:58 UTC