Post by TonyLet a,b be two points of the Klein bottle K. Let X be the identification
space we get by identifying a and b. How can I calculate the fundamental
group of X? I am thinking Seifert Van Kampen theorem, but not sure how I
could apply it. Does it matter which two points I pick?
Tony
The direct usage of Seifert & van Kampen's theorem might be a bit messy,
because the obvious decomposition of this space (take a closed
neighborhood of the identification point, and the closure of the
complement) produces a non-connected intersection.
Instead, note that the identification space, which I'll call K', is
homotopy equivalent to the one-point union (otherwise called the
"wedge") of K with a circle:
K' ~ K v S^1.
The details are simple, but messy. Here's the visualization:
Imagine the point [ab] in K' corresponding to the
identification of a and b is a gob of glue that
hasn't dried, and pull them apart slowly. The glue
will produce a thread joining those points.
Now, do it properly: Let K" denote the union of K with an arc I_ab
joining a and b (otherwise disjoint from K). There is an obvious
map of K" to K' that collapses I_ab to [ab]. The other direction is
less obvious to the beginner, and somewhat tedious: take small discs
surrounding a and b and map the one-point union (identifying a and b)
to the segment I_ab using the radial coordinate; take up the slack by
expanding the radial coordinate in small annular regions around the
original discs, and leave the rest of K' alone. Details and proof that
you get a homotopy equivalence are left to you.
Now that you've got K' ~ K", note that you can move the endpoints of
the arc I_ab without changing the homotopy type of K", and in fact
you can put the endpoints at the same location in K, still within
that homotopy type.
This gives you K' ~ K v S^1, and you can surely use the above-mentioned
theorem, but it's really overkill.
Dale.