bassam king karzeddin

2017-01-17 17:44:44 UTC

Reply

Permalink(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Discussion:

Add Reply

bassam king karzeddin

2017-01-17 17:44:44 UTC

Reply

Permalink(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Efftard K. Donglemeier

2017-01-21 22:39:58 UTC

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Permalink
a***@gmail.com

2017-01-22 18:11:01 UTC

Reply

Permalinksuch an equation seems simple enough ... that is that

nobody gAf about it, unless a g00d query can be made

bassam king karzeddin

2017-01-24 09:43:21 UTC

Reply

Permalinkin part is just his lack of grammar\english, but

such an equation seems simple enough ... that is that

nobody gAf about it, unless a g00d query can be made

Of course nobody can solve it, except me!

but I do not want to spoil the joy of solving it!

So, enjoy it for the rest of your life mythematickers

Regards

Bassam King karzeddin

24th, Jan., 2016

a***@gmail.com

2017-01-24 22:49:59 UTC

Reply

Permalinkif I "see the light" of the wonder of that,

I'll at least not think t00 much about it

Of course nobody can solve it, except me!

but I do not want to spoil the joy of solving it!

bassam king karzeddin

2017-01-25 15:44:36 UTC

Reply

PermalinkI have problems that I want to do, but

if I "see the light" of the wonder of that,

I'll at least not think t00 much about it

Of course nobody can solve it, except me!

but I do not want to spoil the joy of solving it!

And so naturally a troll who provides such a problems for mathematicians, because he wanted to torture them to death, not wanting them to even sleep peacefully

Imagine if this same (very little) problem was provided by a very well known mathematician, then see how things would seem too different, even to you readers

First: it would be documented very well in very reputable sources

Second: they would make international conferences about this puzzels

Third: the historians would immediately make some novel book stories about the puzzle, especially if the puzzler pass away

Forth: they would start offering prizes to the puzzle

Fifth: many of the Wikipedia writers would immediately start their yellow pages about it

Fifth: many of the secretive researchers would start submitting their papers of partial results towards the final proof or so

Sixth: many books and internet sites would be written about this puzzel

there are als many more points not present in mind, ...

So, do not ask your teachers or the teachers of your teachers about it, let them first solve that called Beal's conjecture, it may be more convenient, since it was established by a millionaire or so, and there is also one million dollar for it, and may be this one comes from that one, or else, who knows?

Regards

Bassam King Karzeddin

25th, Jan., 2017

b***@gmail.com

2017-01-25 15:52:21 UTC

Reply

PermalinkAnd so naturally a troll who provides such a problems for

mathematicians, because he wanted to torture them to death,

not wanting them to even sleep peacefully

bassam king karzeddin

2017-01-25 16:13:56 UTC

Reply

PermalinkInteresting research goal. Good one, please continue.

And so naturally a troll who provides such a problems for

mathematicians, because he wanted to torture them to death,

not wanting them to even sleep peacefully

bassam king karzeddin

2017-01-25 17:03:22 UTC

Reply

PermalinkInteresting research goal. Good one, please continue.

And so naturally a troll who provides such a problems for

mathematicians, because he wanted to torture them to death,

not wanting them to even sleep peacefully

BK

a***@gmail.com

2017-01-25 21:57:29 UTC

Reply

Permalinkof that there are no rational solutions to "the last equation,"

but that seems to be all that you like to chatter about, botty

So, do not ask your teachers or the teachers of your teachers about it, let them first solve that called Beal's conjecture, it may be more convenient, since it was established by a millionaire or so, and there is also one million dollar for it, and may be this one comes from that one, or else, who knows?

Regards

Bassam King Karzeddin

25th, Jan., 2017

a***@gmail.com

2017-01-26 00:20:23 UTC

Reply

Permalinkyou posted that sylli equation; certainly,

that is a nice exemplar of the problem, d00d

bassam king karzeddin

2017-01-26 11:07:49 UTC

Reply

Permalinkoh, but, now, I see, why,

you posted that sylli equation; certainly,

that is a nice exemplar of the problem, d00d

Yes it is a very silly problem as you can see, it should had been done much before Fermate had stated his wonderful conjecture, same applies for Beal's conjecture

They were all stored in that only theorem of Pythagoras, then there was no need to have so many eggs once you have the hen, but this is still difficult for you I suppose

One keeps wondering why the Pythagoreans didn't make at all?

BK

a***@gmail.com

2017-01-26 18:58:13 UTC

Reply

Permalinkwhether there are any more Fermat primes;

there are certainly no more, beyond the finities searched by algorithm

if you do not even know Fermat's little theorem,

there is certianly no hope for your problemmas

They were all stored in that only theorem of Pythagoras, then there was no need to have so many eggs once you have the hen, but this is still difficult for you I suppose

One keeps wondering why the Pythagoreans didn't make at all?

can you even find the seventh p.t, or

the first pythagorean quadruple?

bassam king karzeddin

2017-01-28 16:19:53 UTC

Reply

PermalinkI solved the only open problem of Fermat's,

whether there are any more Fermat primes;

there are certainly no more, beyond the finities searched by algorithm

if you do not even know Fermat's little theorem,

there is certianly no hope for your problemmas

They were all stored in that only theorem of Pythagoras, then there was no need to have so many eggs once you have the hen, but this is still difficult for you I suppose

One keeps wondering why the Pythagoreans didn't make at all?

can you even find the seventh p.t, or

the first pythagorean quadruple?

Do you mean like this (15^7 + 37969^2 = 40156^2)

BK

bassam king karzeddin

2017-01-29 15:46:55 UTC

Reply

PermalinkI solved the only open problem of Fermat's,

whether there are any more Fermat primes;

there are certainly no more, beyond the finities searched by algorithm

if you do not even know Fermat's little theorem,

there is certianly no hope for your problemmas

They were all stored in that only theorem of Pythagoras, then there was no need to have so many eggs once you have the hen, but this is still difficult for you I suppose

One keeps wondering why the Pythagoreans didn't make at all?

can you even find the seventh p.t, or

the first pythagorean quadruple?

Do you mean like this (15^7 + 37969^2 = 40156^2)

BK

x^n + y^2 = z^2

BK

a***@gmail.com

2017-01-31 01:42:29 UTC

Reply

Permalinkthe problem of the perfect box is just the pythagorean theorem,

but there are two spatial ones

Those had nothing with Fermat's, they are more basic than Fermat's

Do you mean like this (15^7 + 37969^2 = 40156^2)

BK

bassam king karzeddin

2017-10-01 16:59:12 UTC

Reply

PermalinkI have problems that I want to do, but

if I "see the light" of the wonder of that,

I'll at least not think t00 much about it

Of course nobody can solve it, except me!

but I do not want to spoil the joy of solving it!

And so naturally a troll who provides such a problems for mathematicians, because he wanted to torture them to death, not wanting them to even sleep peacefully

Imagine if this same (very little) problem was provided by a very well known mathematician, then see how things would seem too different, even to you readers

First: it would be documented very well in very reputable sources

Second: they would make international conferences about this puzzels

Third: the historians would immediately make some novel book stories about the puzzle, especially if the puzzler pass away

Forth: they would start offering prizes to the puzzle

Fifth: many of the Wikipedia writers would immediately start their yellow pages about it

Fifth: many of the secretive researchers would start submitting their papers of partial results towards the final proof or so

Sixth: many books and internet sites would be written about this puzzel

there are als many more points not present in mind, ...

So, do not ask your teachers or the teachers of your teachers about it, let them first solve that called Beal's conjecture, it may be more convenient, since it was established by a millionaire or so, and there is also one million dollar for it, and may be this one comes from that one, or else, who knows?

Regards

Bassam King Karzeddin

25th, Jan., 2017

Believe it, this one should have more than one million $ prize

But hey, don't rely on your computer much, since the computer despite being very useful but it is usually quite dumped for sure

Regards

BKK

bassam king karzeddin

2017-01-29 18:15:51 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

https://www.quora.com/What-is-your-favorite-Diophantine-equation/answer/Bassam-Karzeddin-1

I do not know if they allow you to read this page at Quora, where I may think they would delete it

I guess also many of you report abuse for my articles, since I saw this on mobile, where all the good topics are hidden, since most people can not tolerate to look into mirror, because they would see something that is not pleasant, Wonder!

BK

bassam king karzeddin

2017-04-15 09:45:21 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BK

bassam king karzeddin

2017-04-17 17:36:05 UTC

Reply

PermalinkOn Tuesday, January 17, 2017 at 9:00:05 PM UTC+3,

supercomputers, cannot find a single triplet integer

solution for this Diophantine equation?

coprime integers, (p > 7) is prime number, and (z =/=

-1)

By this simple one line statement about trinomial

l Diophantine equations, a bitter end had been set to

many other secretive researchers dreams in this

field, and for sure

BK

I really did not mean to kill the mathematicians dreams, but to enlighten them that there are more interesting thing to do instead of wasting your life aimlessly for suresupercomputers, cannot find a single triplet integer

solution for this Diophantine equation?

coprime integers, (p > 7) is prime number, and (z =/=

-1)

By this simple one line statement about trinomial

l Diophantine equations, a bitter end had been set to

many other secretive researchers dreams in this

field, and for sure

BK

But, so unfortunately I had already and unintentionally collapsed so many other basic areas in mathematics too, to unbelievable degree that had never occurred in the fabricated fake history of mathematics

In fact I had succeeded beyond limits to reduce it to be good enough for our little carpentry works for sure

But, do not think that is the horrible end of the modern mathematics

There are so much real true hidden and uncovered mathematics that is more than sufficient for everybody, and for sure

BK

bassam king karzeddin

2017-04-19 20:14:09 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

That is why they keep hiding it

Hey, but here is not MSE or Quora OR any other moron moderated site that you can practice your illness and so incompetence for sure

Here every thing remains documented to a date and a second and hopefully forever

And here is no dirty hand or diseased criminal mind can simply delete, modify, hide or spoil your content (whatever it is)

Here is a free world based on equal grounds and away from those moron professionals whom are more than helpless in this regard, for sure

BK

bassam king karzeddin

2017-04-24 15:48:00 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But this may be good enough for you to think better, at least you can add one more term and start again from the beginning

Why do I call upon number theorist mainly, because you know that mathematicians are only those number theorists, but the rest are arguing aimlessly for something not necessarily mathematics, for sure

BK

bassam king karzeddin

2017-04-29 18:33:43 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Is not this one conjecture is much stronger than a famous CONJECTURE made by a mature bilinear as (Beal's Conjecture), and also documented in so many sources for sure

Or is it necessary to be a bilinear to make conjectures for the top professional mathematicians, wonder?

Do not they feel so shameless to keep hiding it forever?

Do not they feel so shameless to torture the future generations of their a like by ignoring it so deliberately and out of complete inability?

OR maybe the so tiny ego they enjoy and intrinsically inherit is the main objection!wonder!

Then why a mature not from their unnoticeable category would help them in this regard?

Or do they make themselves as deaf and blind as always as usual?

Or do they want to fabricate a good reputable source about it first?

Maybe they are still so busy searching mathematics in far galaxies, wonder!

And they would never dare to understand that (why a skilled football player is much more worth than all of them on earth, including their main historical figures nowadays), wonder!

And they would never dare to understand why a mature (not from their category), had been shaming and cursing them for four centuries, and most likely forever, (even they had a proof), wonder!

And the so wonderful story of that unforgettable shame that had been published by his son and not by them for sure

But in their fabricated history, and without all those advanced communications

tools made by Scientists and Engineers, (they so shamelessly claim to be nobles), to the limit that they found the greatest theorems written in the rubbish papers written by dead boys, they still keep, wonderfull

So, if you are a talented mature, then you can paint those people with shame for sure

And my puzzles would act permanently as a real curse upon their so tiny alleged intelligence for sure

This is a general critique to uncover this meaningless category of abnormal human beings, and not pointed or directed to anyone in person, for sure

BK

bassam king karzeddin

2017-05-06 09:59:12 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Consider only (p = 11), then the following distinct Diophantine equation has no integer solution (except for NEGATIVE unity (z = -1)) as stated earlier!

(X^3 + Y^2 + Z^11 = 0)

And I am so sorry to make your personal computer as useless in this case, but let us try to bother that lazy, called a super computer!

And if the blue computer can not help, then guess what does this mean? wonder!

BK

bassam king karzeddin

2017-05-08 16:21:14 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Otherwise, this would go immediately to the top news of that unnoticeable world of mathematics

But never mind, let me offer a modest prize of say (300 $), first, however, anyone is free to increase the amounts of the prize for any counter example or a rigorous proof, for sure

BK

bassam king karzeddin

2017-05-09 18:02:38 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Otherwise, this would go immediately to the top news of that unnoticeable world of mathematics

But never mind, let me offer a modest prize of say (300 $), first, however, anyone is free to increase the amounts of the prize for any counter example or a rigorous proof, for sure

BK

Or maybe there isn't any number theorist in this century, maybe, wonder!

Or maybe it is too tough problem for you, for sure

and the challenge is not mainly for your ability, but for the whole technology of supercomputers ability, for sure

BK

bassam king karzeddin

2017-05-13 09:16:19 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Otherwise, this would go immediately to the top news of that unnoticeable world of mathematics

But never mind, let me offer a modest prize of say (300 $), first, however, anyone is free to increase the amounts of the prize for any counter example or a rigorous proof, for sure

BK

And who knows if this Prize would become worth more than 3 million $ in the future, wonder!

Good luck students

BKK

bassam king karzeddin

2017-07-26 13:57:59 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Otherwise, this would go immediately to the top news of that unnoticeable world of mathematics

But never mind, let me offer a modest prize of say (300 $), first, however, anyone is free to increase the amounts of the prize for any counter example or a rigorous proof, for sure

BK

And who knows if this Prize would become worth more than 3 million $ in the future, wonder!

Good luck students

BKK

BKK

b***@gmail.com

2017-07-26 14:19:09 UTC

Reply

Permalink(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

b***@gmail.com

2017-07-26 14:25:59 UTC

Reply

Permalinkreal numbers. I said could, since it only says there are

finitely many x,y from integers such that:

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

bassam king karzeddin

2017-07-26 16:33:57 UTC

Reply

PermalinkBTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

b***@gmail.com

2017-07-26 16:58:28 UTC

Reply

Permalinky^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

bassam king karzeddin

2017-07-26 17:26:38 UTC

Reply

Permalinky^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

So many, and so what?

All those issues are so irrelevant to my simple plain conjecture, for sure

And you have no good point at all

OR is it not permitted to announce any interesting results from such as sci.math group? wonder!

But what about those alleged trusted reputable sources once they can't comprehend or state such puzzles?

Or must we wait for their needless permission to state our theorems here also, wonder!

Weren't the rubbish papers the richest resources for that claiming to be the most reputable sources Journals and Universities made by Dead and were forgotten, people? wonder!

And you will get ZERO point as usual, for sure

BKK

b***@gmail.com

2017-07-26 18:33:01 UTC

Reply

Permalinky^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points (x,y) do you see BKK?

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

So many, and so what?

All those issues are so irrelevant to my simple plain conjecture, for sure

And you have no good point at all

OR is it not permitted to announce any interesting results from such as sci.math group? wonder!

But what about those alleged trusted reputable sources once they can't comprehend or state such puzzles?

Or must we wait for their needless permission to state our theorems here also, wonder!

Weren't the rubbish papers the richest resources for that claiming to be the most reputable sources Journals and Universities made by Dead and were forgotten, people? wonder!

And you will get ZERO point as usual, for sure

BKK

b***@gmail.com

2017-07-26 18:57:33 UTC

Reply

Permalinky^2 + x^3 = n

Is the mirror of this curve:

y^2 = x^3 + n

Proof: Use x1=-x2, then we have

y^2 + x1^3 = n

y^2 + (-x2)^3 = n

y^2 + - (x2^3) = n

y^2 = x2^3 + n

Check for yourself:

https://www.wolframalpha.com/input/?i=y^2+%2B+x^3++%3D+1

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3+%2B+1

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points (x,y) do you see BKK?

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

So many, and so what?

All those issues are so irrelevant to my simple plain conjecture, for sure

And you have no good point at all

OR is it not permitted to announce any interesting results from such as sci.math group? wonder!

But what about those alleged trusted reputable sources once they can't comprehend or state such puzzles?

Or must we wait for their needless permission to state our theorems here also, wonder!

Weren't the rubbish papers the richest resources for that claiming to be the most reputable sources Journals and Universities made by Dead and were forgotten, people? wonder!

And you will get ZERO point as usual, for sure

BKK

bassam king karzeddin

2017-07-27 07:43:19 UTC

Reply

Permalinky^2 + x^3 = n

y^2 = x^3 + n

Proof: Use x1=-x2, then we have

y^2 + x1^3 = n

y^2 + (-x2)^3 = n

y^2 + - (x2^3) = n

y^2 = x2^3 + n

https://www.wolframalpha.com/input/?i=y^2+%2B+x^3++%3D+1

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3+%2B+1

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points (x,y) do you see BKK?

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

So many, and so what?

All those issues are so irrelevant to my simple plain conjecture, for sure

And you have no good point at all

OR is it not permitted to announce any interesting results from such as sci.math group? wonder!

But what about those alleged trusted reputable sources once they can't comprehend or state such puzzles?

Or must we wait for their needless permission to state our theorems here also, wonder!

Weren't the rubbish papers the richest resources for that claiming to be the most reputable sources Journals and Universities made by Dead and were forgotten, people? wonder!

And you will get ZERO point as usual, for sure

BKK

Did anyone before me state clearly my claimed conjecture here?

Most likely the historian professionals would always prefer to find any kind of a link reference between that meaning especially from the past

OR: Are mathematical conjectures allowed to be published in a place supposed to be for mathematicians and mathematical sciences? wonder!

BKK

b***@gmail.com

2017-07-27 09:20:57 UTC

Reply

Permalinky^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points (x,y) do you see BKK?

y^2 = x^3+x

https://www.wolframalpha.com/input/?i=y^2+%3D+x^3%2Bx

How many points do you see BKK?

BTW: The curve could be a nice example for the existence of

real numbers. I said could, since it only says there are

y^2 = x^3 + n

Do have some curves statements, such as there are only

a finitely many rational numbers x,y?

Then since its a curve, we probably assume there are infinitely

many points, we could conclude that the other points are

irrational (maybe only one component),

and somehow, that they exist.

https://math.stackexchange.com/questions/113340/elliptic-curves-with-finitely-many-rational-points

https://en.wikipedia.org/wiki/Mordell_curve

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

BKK

So many, and so what?

All those issues are so irrelevant to my simple plain conjecture, for sure

And you have no good point at all

OR is it not permitted to announce any interesting results from such as sci.math group? wonder!

But what about those alleged trusted reputable sources once they can't comprehend or state such puzzles?

Or must we wait for their needless permission to state our theorems here also, wonder!

Weren't the rubbish papers the richest resources for that claiming to be the most reputable sources Journals and Universities made by Dead and were forgotten, people? wonder!

And you will get ZERO point as usual, for sure

BKK

bassam king karzeddin

2017-08-07 09:28:39 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Otherwise, this would go immediately to the top news of that unnoticeable world of mathematics

But never mind, let me offer a modest prize of say (300 $), first, however, anyone is free to increase the amounts of the prize for any counter example or a rigorous proof, for sure

BK

And who knows if this Prize would become worth more than 3 million $ in the future, wonder!

Good luck students

BKK

BKK

BKK

Python

2017-07-26 15:24:37 UTC

bassam king karzeddin

2017-07-26 16:21:43 UTC

Reply

PermalinkAnd the real tragedy is indeed when the vast majoritites are the ignorants and the little minority are the very cowards

But this is already the case from the DOCUMENTED history, where ignorants never learn or even want to learn for sure

BKK

bassam king karzeddin

2017-05-11 14:44:31 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Had I written that damn conjecture in a margin of a notebook to myself in the hope that my son would publish it after 10 years of my death, would have been a better idea than publishing it quite many times to the whole world in a place that is globally supposedly meant for SCIENCE and particularly for MATHEMATICS and MATHEMATICIANS, wonder!

But the whole problem is that my son doesn't like all the mathematics at all, for sure

BKK

Python

2017-05-11 14:55:18 UTC

Reply

PermalinkBut the whole problem is that my son doesn't like all the mathematics at all, for sure

bassam king karzeddin

2017-05-11 16:04:18 UTC

Reply

PermalinkBut the whole problem is that my son doesn't like all the mathematics at all, for sure

BKK

b***@gmail.com

2017-07-28 07:25:33 UTC

Reply

PermalinkHenri Cohen Number Theory Volume II:

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

b***@gmail.com

2017-07-28 07:36:34 UTC

Reply

PermalinkBut (x,y,z)=(7,13,-2) are all co-prime.

From work by Darmon and Granville, if 1/p+1/q+1/r<1,

then the equation a*x^p+b*y^q+c*z^r=0 has only finitely

many coprime solutions. Same source.

r=11, so we might not have a solution different from:

2^3 + (-3)^2 + 1^11 = 0

7^3 + 13^2 + (-2)^9 = 0

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

b***@gmail.com

2017-07-28 07:45:09 UTC

Reply

Permalink"While waiting for my döner at lunch the other day, I noticed ..."

https://math.stackexchange.com/q/2373028/4414

Oops, sorry p = 9 is not prime.

But (x,y,z)=(7,13,-2) are all co-prime.

From work by Darmon and Granville, if 1/p+1/q+1/r<1,

then the equation a*x^p+b*y^q+c*z^r=0 has only finitely

many coprime solutions. Same source.

2^3 + (-3)^2 + 1^11 = 0

7^3 + 13^2 + (-2)^9 = 0

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2017-07-29 07:24:45 UTC

Reply

Permalink"While waiting for my döner at lunch the other day, I noticed ..."

https://math.stackexchange.com/q/2373028/4414

Oops, sorry p = 9 is not prime.

But (x,y,z)=(7,13,-2) are all co-prime.

From work by Darmon and Granville, if 1/p+1/q+1/r<1,

then the equation a*x^p+b*y^q+c*z^r=0 has only finitely

many coprime solutions. Same source.

2^3 + (-3)^2 + 1^11 = 0

7^3 + 13^2 + (-2)^9 = 0

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Listen carefully Encyclopedia Moron, There are many issues that can be so easily taught to the public and top professionals mathematicians, but frankly, they would never appreciate anything, and on the contrary, they would become more hostile and so deniers, so no need to bother them at all, hence let them know its truthiness from its fakeness by their own brain fart, and the auction is continuing for sure

Say (700) USA $, now

But frankly, I am so afraid of the artificial intelligence, wonder!

So, no need even to say Good Luck, for sure

Regards

Bassam King Karzeddin

07/29/2017

bassam king karzeddin

2017-08-07 09:36:24 UTC

Reply

Permalink"While waiting for my döner at lunch the other day, I noticed ..."

https://math.stackexchange.com/q/2373028/4414

Oops, sorry p = 9 is not prime.

But (x,y,z)=(7,13,-2) are all co-prime.

From work by Darmon and Granville, if 1/p+1/q+1/r<1,

then the equation a*x^p+b*y^q+c*z^r=0 has only finitely

many coprime solutions. Same source.

2^3 + (-3)^2 + 1^11 = 0

7^3 + 13^2 + (-2)^9 = 0

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

So, whom are you trying to cheat here, maybe the cheap sheep you mean? wonder!

Also, see the recent dates in your reference

You who needs a doctor for sure

BKK

bassam king karzeddin

2017-08-07 09:41:21 UTC

Reply

Permalink"While waiting for my döner at lunch the other day, I noticed ..."

https://math.stackexchange.com/q/2373028/4414

Oops, sorry p = 9 is not prime.

But (x,y,z)=(7,13,-2) are all co-prime.

From work by Darmon and Granville, if 1/p+1/q+1/r<1,

then the equation a*x^p+b*y^q+c*z^r=0 has only finitely

many coprime solutions. Same source.

2^3 + (-3)^2 + 1^11 = 0

7^3 + 13^2 + (-2)^9 = 0

Analytic and Modern Tools - 2007

http://www.springer.com/in/book/9780387498935

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

So, whom are you trying to cheat here, maybe the cheap sheep you mean? wonder!

Also, see the recent dates in your reference

You who needs a doctor for sure

BKK

bassam king karzeddin

2017-07-31 14:42:01 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Then, let it be a wonderful piece of stamp of shame printed on every forehead alleged genius mathematicians who ignore it DELIBERATELY for sure

BKK

bassam king karzeddin

2017-08-06 12:52:55 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

So, this is the modern mathematician's attitudes and behaviours (that is all)

And later, after nearly a century someone would gladly go throw it where others would claim that they had never seen it or heard about it, for sure

BKK

bassam king karzeddin

2017-08-09 11:37:43 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

(number theorists) enjoy it the rest of your life, and pass it also to your future generations for more and more entertainment for sure

At least, one day they would certainly find many of you (with their documented words) to make so much fun for sure

BKK

bassam king karzeddin

2017-09-12 08:47:14 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2017-09-20 17:49:03 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-09-24 18:34:47 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But hey, never worry, after few generations, and assuming the artificial intelligence get so advanced, your grandkids would believe in it ultimately, exactly like you do believe now in theorems that certainly you don't have a real clue to it, for sure

Didn't ask your PC? but so ashamed to say what does it tell you (at least with its limited capacity)

So, go and ask your best teachers now?

But make sure that they can never help you in those matters since there is a number theory, Diophantine Equations that you can't mock up like you often do with real numbers

And here you might understand what does the word existence means exactly in mathematics

The rest of maths is really carpentry works

And get tortured with this theorem also, since you really don't deserve to evolve at all, for sure

BKK

bassam king karzeddin

2017-09-27 15:07:54 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But I think that they say it is a much harder problem than Fermat's last theorem in the number theory, wonder!

Here is the link: http://www.mathe2.uni-bayreuth.de/stoll/schrift.html

BKK

bassam king karzeddin

2017-09-30 14:06:27 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But I think that they say it is a much harder problem than Fermat's last theorem in the number theory, wonder!

Here is the link: http://www.mathe2.uni-bayreuth.de/stoll/schrift.html

BKK

But truly, I should thank those who shared an opinion (with real identities of course), despite the fact that they had hardly contributed anything useful to the issue

BKK

Pancho ValveJob

2017-09-30 14:13:14 UTC

Reply

Permalink
bassam king karzeddin

2017-09-30 14:31:13 UTC

Reply

PermalinkBKK

bassam king karzeddin

2017-10-07 08:18:10 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-10-07 09:28:28 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

And here come and say something meaningful if you really can, wonder!

BKK

bassam king karzeddin

2017-10-11 16:31:02 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-10-15 09:05:17 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But there is only one dishonourable choice left for you and no other for sure, and you know it exactly, don't you? wonder!

Just ignore it, and that is all

BKK

bassam king karzeddin

2017-10-16 08:48:20 UTC

Reply

PermalinkWhy the top mathematicians with the help of

supercomputers, cannot find a single triplet integer

solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero

o coprime integers, (p > 7) is prime number, and (z

=/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

I swear, I never wanted to hurt anyone's so sensitive feelings and never once imagined that irrefutable theorems (conjectures for you) may cause or create a lot of problems for people, really be wondering if math is becoming so boring up to this limit for mainly for the professional mathematicians for sure

However, it is only one line statement and no more, so unlike many published papers that you get bored to death of its size and tonnes of references

I really do apologize for you people in this century, but my true intention are those waiting in the coming centuries for sure since frankly, I know very well your limits on those superior sensitive issues

And later (once people become intelligent enough by the help of brain aid device) and your grandsons would curse you for trying to hide any of my topics

So, if you are truly helpless, then at least keep it for new generations, since I know there isn't Stack- Exchange or Quora or Moderated sites here, otherwise I won't bother even to write it, and I would take it with me to my stone grave for sure

And remember that you are living in a supercomputer age for sure

I'm I asking you to do miracles? wonder!

Regards

Bassam King Karzeddin

Oct. 16th, 2017

bassam king karzeddin

2017-10-23 19:12:06 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

So, keep trying, because once you can, then certainly you would smartly manage and also fabricate all the other accessories, then suddenly change your rotten mind for more than sure

BKK

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2017-10-31 18:46:59 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But why do you prefer absolute silence here? wonder!

Can't you use your SUPERCOMPUTER? wonder!

Frankly, I hardly can use a calculator

But, maybe many other reasons that you know secretly whenever you stand with your self before a mirror!wonder!

Are you still so shameful to ask your brain masters about it? wonder!

Or maybe waiting for another century to enjoy it later? wonder!

So, please look again carefully and so secretly in your mirror and be brave enough to confess and say what did you see exactly? wonder!

And don't bother for your children to save, since they would have lots of fun with it and for sure, but maybe that brain aid device would help a lot in those matters, who knows? wonder!

So, go and hide and make your self-deaf, and blind too, after all, it is not yours then who cares too? wonder!

But so frankly, I do always enjoy bringing you to a real mirror, where certainly you see something that you never like for sure

But even that doesn't any matter for sure

By the way, I do have much more for sure

Regards

Bassam King Karzeddin

Oct. 31st, 2017

Why the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2017-11-04 11:56:55 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-11-06 08:13:08 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Where are you hiding now?

Where are your long tounges that usually get together into so many talkative issues that usually anyone can talk even with a very little background especially in any issue that contradicts mathematics?

What can you add here except a gibberish that usually is your contribution?

Didn't you still fabricate some historical references for this so silly problem?

Didn't you inform your alleged brain masters about it yet?

Didn't they tell you frankly to avoid the King true attacks in those special issues?

And what other choice is left for you and for your brain masters in this regard? wonder!

Do you really understand what issue I'm talking about? wonder!

So, back to your tinny holes as clueless as warm earth for sure

BKK

bassam king karzeddin

2017-11-07 14:51:09 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Where are you hiding now?

Where are your long tounges that usually get together into so many talkative issues that usually anyone can talk even with a very little background especially in any issue that contradicts mathematics?

What can you add here except a gibberish that usually is your contribution?

Didn't you still fabricate some historical references for this so silly problem?

Didn't you inform your alleged brain masters about it yet?

Didn't they tell you frankly to avoid the King true attacks in those special issues?

And what other choice is left for you and for your brain masters in this regard? wonder!

Do you really understand what issue I'm talking about? wonder!

So, back to your tinny holes as clueless as warm earth for sure

BKK

So, keep silent forever as always as usual

BKK

bassam king karzeddin

2017-11-15 18:45:37 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

then I told him, ask everyone around but never ask any professional mathematicians?

So, he asked me why?

I said, all the historical novel stories fabricated in the history of mathematics about the alleged nobilities of mathematicians are actually fabricated, exactly like they're many leged real or complex numbers and many other things that had been well-exposed mainly at sci.math google. since no dirty human hands can change or touch, for sure

BKK

bassam king karzeddin

2017-11-18 15:49:23 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Regards

bassam king karzeddin

2017-11-21 18:11:36 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But it seems that was my destiny

BKK

bassam king karzeddin

2017-11-26 19:38:32 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But truly, they had got very frustrated since this not from past nor from their well known current morons that are filling the galaxy, for sure

BKK

bassam king karzeddin

2017-11-27 17:55:49 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-11-30 19:17:35 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-12-06 17:40:09 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-12-09 18:38:36 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2017-12-11 08:14:04 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2017-12-16 08:20:19 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-01-07 13:54:43 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-01-08 12:30:42 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Instead, the more honorable way for normal mathematicians (if at all existing) is to realize it immediately and make it front page news at least as a New Conjecture for you (especially and more shamefully you are living in a supercomputer ages) wonder!

But what can you hope from a so negligible and so unnoticeable category of human being as mathematicians? nothing for sure

But their canny nature of searching old papers of dead people would certainly realize it even after so many centuries for sure

And once mathematicians riseup up to the level of football audience, then there maybe a hope

Or maybe they wanted it the usual way of authority publication standard, (from alleged top Journal or top University or top known mathematicians), then it will make the biggest difference for the little dwarfs, for sure

But till that time, enjoy it a lot, and get more tortured with it, with so much shame that would paint you from your tiny heads to your big foots, for sure

Don't forget it also to fabricate old claims for this theorem once you need it.

BKK

bassam king karzeddin

2018-01-09 08:17:31 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Maybe they are too busy covering the football news in so colorful front full pages of this world top news, wonder!

Or maybe they are there getting ready for it but not in this silly century, wonder!

Or maybe some other devilish force (mainly within YOU) that isn't allowing you to speak, because they know very well what are the natural consequences, wonder!

And forget completely about your alleged nobility stories that were well planted in your fabricated forged history.

So, be tortured and painted with shame till you get ready

Here is a real true public history with exact dates, that isn't made by one man show for many diry purposes, for sure

BKK

bassam king karzeddin

2018-01-16 09:33:34 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-01-16 12:37:28 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

And we do know very well the true reasons that need not to be mentioned again and again for sure

BKK

bassam king karzeddin

2018-01-20 19:32:35 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But this is a fact that you can't do anything about it, sure

BKK

bassam king karzeddin

2018-01-22 15:18:19 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-01-24 15:23:05 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Had they given up searches or abandoned number theory and mathematics it self ? wonder!

But it seems that the whole issue seems personal for them and never the true mathematics itself, wonder!

So, we will keep hammering them until they completely surrender, for sure

BKK

bassam king karzeddin

2018-01-25 09:35:59 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

1) Conjectures must be published only by a reputable Journal or reputable university or reputable well-known mathematician in power with a proven record of high performance in mathematics, hence strictly prohibited for outsiders

2) No harm to consider any standing and still challenging conjecture provided that the claimer must not be alive anymore, and a mathematician in power only must be eligible to investigate it and make books or papers about it

3) Claimed conjectures in number theory aren't at all important as the importance of who published it and where

4) Internet free sources are not at all important sources, but a talented known mathematicians in power may make it with a bit of change and fabricating any alleged old documented hints to it with tons of professional details references that would ultimately invalidate its true obvious sources

5) Great Conjectures are strictly prohibited to be stated by anyone that is never known and well recognized by the mathematical communities

6) Conjectures must be written in java style script or so and so and so...

7) You can also suggest any or many additional requirements that must obey the rules of publishing any challenging conjectures, as for instance, age must be under 40 years and above 20, height must be less than 170 cm and above say one meter long, weight of claimer must be strictly less than 100 kg and above 20 kg, colour must be .....etc, etc

But the king says that he had got fed up with your many meaningless requirements and never wants anything from you, but wants to torture you with such conjectures as long as you are alive (even you are so lucky to live in an era of supercomputer age that is almost available to every alleged genius professional moron), and basically because of your many and very bad traits of incurred egoistic physiological problems of being big liers, absolute inherited stupidity, cowardness and dishonesty as well.

No regards at all, BUT deep Insults to your alleged intelligence, nobility and alleged honosity as well, for sure

Bassam King Karzeddin

Jan. 25th, 2018

bassam king karzeddin

2018-01-29 07:42:12 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-02-01 14:08:27 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

So let your poor devices save you from the KING

So, keep hoping forever and for sure

BKK

bassam king karzeddin

2018-02-05 06:08:10 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

1) And once the highest technology couldn't help him in this regard, he would try desperately to find any historical hint (no matter if it is not exactly related) so that he can build on and conclude deliberately and so cowardly and so shamelessly that conjecture is from that older source, then it becomes more interesting to swim in it, where some others might establish truly very fabricated forged resources

2) If all this fails, he would see with much more importance to the person who claimed it whether he is well-known mathematician and was graduated from an alleged highly reputable university or so and so ...

3) If all this fails again, he would ask where were this was published first and more silly questions than you may imagine

4) If all this fails again and again, he then would choose to keep silent and pretends stubbornly that he never heard or saw such a conjecture because according to his silly and deliberate so foolish understanding, the word "publish" means only publish in well-known Journals, or well-known university or by a well-known mathematician

But, we can confidently tell you that the word "publish" means publish everywhere you think it is suitable, as long as the content is true, for sure

So, it is already PUBLISHED, and it doesn't any matter all your so foolish considerations, for sure

BKK

bassam king karzeddin

2018-02-06 09:53:23 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

bassam king karzeddin

2018-02-08 18:27:08 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-02-11 08:51:13 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

BKK

bassam king karzeddin

2018-02-13 09:54:50 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

And we know in advance that mathematics it self is not at all important for you, but something else in mind that I'm too embarrassed to talk about

So, be painted forever with the biggest shame down from your foot to your upper empty skull box, for sure

No Regards

Bassam King Karzeddin

Feb. 13th, 2018

bassam king karzeddin

2018-02-17 07:11:03 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

https://mathoverflow.net/questions/282112/why-this-diophantine-equation-doesnt-have-any-integer-solution?noredirect=1#comment727393_282112

They put the question on hold for their damn well-known reasons

This question appears to be off-topic, ... and

This question appears to be not of research level....

By few incompetent cranks with their SO tiny negligible names under

Jeremy Rooua, GH from MO, Greg Martin, Filer Voloc, Ben Mehas

But the King would tell them this question is appears to be OFF-Topics of your so tiny and nutty skull boxes of your brains, and was designed to torture you and your alike generations for ever

This question isn't research level in your doomed mathematics, but a top research level question in Physiology of the dwarfs motivations and reactions towards much superior matters of those little apes

And even you delete it at your so exposed site, it is permanently published and forever, just to uncover the so many monkeys that are hiding in plenty every where you go around, for sure

So, instead of taking it to your highest levels, you still want to delete it so shamelessly ans so arrogantly as you did for most of my topics

So, be shamed of your coward acts, forever and for sure

BKK

bassam king karzeddin

2018-02-20 07:00:31 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

https://mathoverflow.net/questions/282112/why-this-diophantine-equation-doesnt-have-any-integer-solution?noredirect=1#comment727393_282112

They put the question on hold for their damn well-known reasons

This question appears to be off-topic, ... and

This question appears to be not of research level....

By few incompetent cranks with their SO tiny negligible names under

Jeremy Rooua, GH from MO, Greg Martin, Filer Voloc, Ben Mehas

But the King would tell them this question is appears to be OFF-Topics of your so tiny and nutty skull boxes of your brains, and was designed to torture you and your alike generations for ever

This question isn't research level in your doomed mathematics, but a top research level question in Physiology of the dwarfs motivations and reactions towards much superior matters of those little apes

And even you delete it at your so exposed site, it is permanently published and forever, just to uncover the so many monkeys that are hiding in plenty every where you go around, for sure

So, instead of taking it to your highest levels, you still want to delete it so shamelessly ans so arrogantly as you did for most of my topics

So, be shamed of your coward acts, forever and for sure

BKK

https://www.quora.com/Why-do-the-moderators-of-MathOverflow-at-SE-put-on-hold-an-irrefutable-conjecture-in-the-elementary-number-theory-instead-of-taking-it-to-the-highest-level-since-we-belong-to-the-supercomputer-age

BKK

bassam king karzeddin

2018-03-01 18:33:43 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

I bet they can't, despite they wish so, but here nobody can so simply (hide, modify, dirt, steal, spoiled, ...etc) anybody else content as he likes

And it is still PUBLISHED GLOBALLY for you so dumb dwarfs at SE, SURE

No regards for so incompetent with so empty skull boxes at SE, SURE

bkk

bassam king karzeddin

2018-05-03 20:08:23 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

Or you can simply believe it in the same way you do indeed believe in so many other things that you confess loudly having no slightest hints or ideas to comprehend them (especially those type of authority publications

Good luck

BK

bassam king karzeddin

2018-07-05 18:53:49 UTC

Reply

PermalinkWhy the top mathematicians with the help of supercomputers, cannot find a single triplet integer solution for this Diophantine equation?

(x^3 + y^2 + z^p = 0), where (x, y, z) are nonzero coprime integers, (p > 7) is prime number, and (z =/= -1)

©

Regards

Bassam King Karzeddin

17th, Jan., 2017

But do you know why? wonder!

Most likely you haven't any single hint yet, sure

A real ignorants world, truly

BK

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