Post by Tim923I'm interested to know the approximate odds of converting a 7-10 split
for a spare in bowling. I've seen different odds: 1/1000, 1/5000,
1/700000.
It has occurred 3 times on television in PBA games. That's all I
know. Has anyone gone thru the math before in this group.
Unlike Blackjack or [fair] dice, bowling involves skill combined with
probability rather than probability alone. Asking the probability of making
this split isn't the same type of question as asking for Blackjack what the
probability of busting by taking a hit on 16 with a fresh set of decks is.
It is player-dependent.
The other poster correctly identified that math:
(# of successes) / (# of attempts)
You could probably get more accuracy by knowing more about the person
throwing the ball and the specific circumstances: age, sex, success at this
type of split, whether making the split is important (which might affect the
level of risk the bowler is willing to carry), etc.
You state that this has occurred 3 times on television in PBA games. Could
this be because the bowler doesn't always try to make the split, or tries
half-heartedly to make it? My understanding is that if you _really_ try to
make this split, you risk striking neither pin. Could it be that the
bowlers aren't _really_ trying?--they are throwing balls guaranteed to hit
one pin or the other, and they're striking the pin off-center and they
_might_ get the other pin but they've positioned the probability
distribution to avoid a gutter ball?
Of course, I don't know how skilled these folks are. My high game bowling
is about 120 ... and in a 7-10 split I'd just aim for one pin or the other
... I'm not sure how much control the pros have.